I see this mentioned quite often in reviews and various threads and wanted to generate some discussion on the topic. The general consensus, with evidence from oscilloscope readings, is that these APVs produce an unfiltered, pulse width modulated, output. Im working on a post that explains pulse width modulation and the difference between filtered and unfiltered outputs in detail, but in general: Pulse Width Modulation (PWM) is using high voltage for a portion of the time and low, or no, voltage for a portion of time to produce an average voltage equal to the set desired voltage. Example: If you set your APV to 3.7v, the PWM profile could be 7.4v for half of the time and 0v for the other half (50% duty cycle), averaging out to 3.7v.
So why does this seem to make a device hit harder that another device set to the same voltage?
Heres my theory, and its fully open to criticism and corrections as needed.
I am not going to type out all the formulas, so here are some references:
Ohm's Law Wheel
Ohm's Law Calculator
Watts is the name of the game. For sake of explanation well use an average voltage of 3.7 and a 1.7 ohm atty/carto. This should produce an output of 8 watts based on Ohms Law.
Lets look at our high voltage of 7.4v. With our 1.7 ohm resistance, Ohms Law tells us that we will have an output of 32 watts during the high voltage time period.
Low voltage period is easy 0 volts, 0 watts.
Now given the example of a 50% duty cycle, even though our average voltage is 3.7v, our average wattage is 16w!
I also believe that the thermodynamics have a lot to do with it. Think of an electric range. If you set the knob on the range to high, how long does it take to go from resting temperature to full heat? Now turn the knob to off. How long does it take to return to resting temperature? Comparatively much longer than it took to heat up. So when thinking about our attys and cartos, we are rapidly heating them with 32 watts, but when we take the power away they are not cooling at the same rate as when they were heated. This results in a higher average temperature than if it were a steady heat at 8 watts.
Open for thoughts...
So why does this seem to make a device hit harder that another device set to the same voltage?
Heres my theory, and its fully open to criticism and corrections as needed.
I am not going to type out all the formulas, so here are some references:
Ohm's Law Wheel
Ohm's Law Calculator
Watts is the name of the game. For sake of explanation well use an average voltage of 3.7 and a 1.7 ohm atty/carto. This should produce an output of 8 watts based on Ohms Law.
Lets look at our high voltage of 7.4v. With our 1.7 ohm resistance, Ohms Law tells us that we will have an output of 32 watts during the high voltage time period.
Low voltage period is easy 0 volts, 0 watts.
Now given the example of a 50% duty cycle, even though our average voltage is 3.7v, our average wattage is 16w!
I also believe that the thermodynamics have a lot to do with it. Think of an electric range. If you set the knob on the range to high, how long does it take to go from resting temperature to full heat? Now turn the knob to off. How long does it take to return to resting temperature? Comparatively much longer than it took to heat up. So when thinking about our attys and cartos, we are rapidly heating them with 32 watts, but when we take the power away they are not cooling at the same rate as when they were heated. This results in a higher average temperature than if it were a steady heat at 8 watts.
Open for thoughts...