Anytime. I thought that looked like my desk and fingers.
I to find that the 5v has way too much flavor loss. But if i want to get a bunch of vapor, very quickly, this is the way to do it.
Cheers all
My 5v Box Mod
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Anytime. I thought that looked like my desk and fingers.
I to find that the 5v has way too much flavor loss. But if i want to get a bunch of vapor, very quickly, this is the way to do it.
Cheers all
1) keep the atty floodedAnytime. I thought that looked like my desk and fingers.
I to find that the 5v has way too much flavor loss. But if i want to get a bunch of vapor, very quickly, this is the way to do it.
Cheers all
2) take shorter draws
I'm loving it now. Was going to give away my other regulators, not now, going to build more boxes
Burnie
I built a 5v box very similar to the one in this thread(just with a 3.7V switch) With the 901 Atty, there does seem to be alot of Flavor loss....tried an 801...Its amazing! Its like the 801 was MADE for 5v's...Check it out...you won't be disappointed
1) keep the atty flooded
2) take shorter draws
I'm loving it now. Was going to give away my other regulators, not now, going to build more boxes
Burnie
That's the spirit Burnie!!! I thought you would have a change of heart once you got the learning curve down. I'm waiting for parts (from china
) so I can finish one of my projects and build my 5v.
I know the feeling waiting for stuff from China, but the price is less than 1/2 the US prices and free freight. I understand the US suppliers wanting to make a profit, but over 100% markup on parts is just crazy. If I purchased 100 batteries I am SURE I could get them cheaper than I am paying now for 2. And also all the US suppliers get them from China too, same stuff, so why the high pricing?That's the spirit Burnie!!! I thought you would have a change of heart once you got the learning curve down. I'm waiting for parts (from china
Burnie
I was wondering about that myself
Burnie
He means a switch that changes from one battery to 2.
So it switches from 5v to 3.7v
_
I was wondering about that myself
Burnie
He means a switch that changes from one battery to 2.
So it switches from 5v to 3.7v
_
Heres the thread...http://www.e-cigarette-forum.com/fo...oltage-regulator-switches-how.html#post482200
and diagram by jeffakamax
Yup, Warp clued us in.... how is that working for you? Any problems?
I've made a lot of electronic projects but nothing where I had to monitor the amperage (much). I've had to fiddle with those voltage regulators, and mini buck coils to step up voltage for use in LED projects.
If I get this wrong sorry, but from what I can tell electric heating elements operate by joule heating, that is, the more current the more heat. Raising the voltage indirectly raises the current which can (I hope) be reduced with a simple resistor. From my calculations (which are probably wrong) you only need about a 3-4 ohm resistor to make 4.8 volts equal to 3.6 @ 2 ohms (a typical atty value). You may want to put like a 10 ohm pot on there and try out different settings.
I've worked with those voltage regulators and they usually reduce voltage by charging tiny caps in series and discharging them in parallel thousands of times a second. The end result is that they lower voltage while raising amperage. On resistive loads this isn't such a big deal, but without a resister the voltage might be lowered but the current (which makes the heat) is actually higher, thus making it kind of useless (I think).
Anyway just my 2 cents.
If I get this wrong sorry, but from what I can tell electric heating elements operate by joule heating, that is, the more current the more heat. Raising the voltage indirectly raises the current which can (I hope) be reduced with a simple resistor. From my calculations (which are probably wrong) you only need about a 3-4 ohm resistor to make 4.8 volts equal to 3.6 @ 2 ohms (a typical atty value). You may want to put like a 10 ohm pot on there and try out different settings.
I've worked with those voltage regulators and they usually reduce voltage by charging tiny caps in series and discharging them in parallel thousands of times a second. The end result is that they lower voltage while raising amperage. On resistive loads this isn't such a big deal, but without a resister the voltage might be lowered but the current (which makes the heat) is actually higher, thus making it kind of useless (I think).
Anyway just my 2 cents.
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