Another Kanthal wire resistance thread

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nebulas

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Let me lay out some fictitious numbers for simplicity sake so I can make my question as clear as possible.

Lets say I have a 3" Kanthal wire that is 1.0ohms per inch giving me a total resistance of 3.0ohms.
Now lets say I take some NR wire and twist it together with 1" of my Kanthal wire.
I then twist another 1" of my Kanthal wire on the other end to another strand of NR wire.
This leaves me with 1" of kanthal wire between each of the NR connections.

At 1.0 ohms per inch, would I have a 1.0ohm wire or would I still have a 3.0ohm wire? Basically, does the connection of the NR wire have any effect on the total resistance of the wire?

I hope I made my question simple enough. :confused:
 

nebulas

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You can't tell that your question is total nonsense?

Hey, wait a minute
Your not really located on Earth, are you?
Thanks for a completely useless post. If I could tell it was nonsense, then I wouldn't be asking it. If you see error in my reasoning or in my question, then it would help to point out the flaws rather than just say "that is nonsense". No such thing as a bad question but obviously bad answers.

I am asking the question because I don't know!
 

AndAllThingsWillEnd

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I don't think it's hard to understand, its actually a question I've been wondering as well.

He's asking if when you twist together the non resistant wire with the resistant wire, does it lower the resistance because of the length of the resistance wire used to twist.

Sent from my Galaxy Nexus using Tapatalk 2
 

BikerBob

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Attempting to understand what you asked:

3 inches long piece of 1-ohm-per-inch kanthal measures 3 ohms resistance.
1 inch of NR wire connected to one end of 1 inch of kanthal wire, and another 1 inch of NR wire connected to other end of kanthal wire. This gives me how much resistance?

If this is indeed what you asked, the total resistance would be 1 ohm. When connected end-to-end, you have 1 inch of 0 ohm, 1 inch of 1 ohm, then 1 inch of 0 ohm. Total is 1 ohm.

The 3 inch length could be thought of as: 1 inch of 1 ohm, then 1 inch of 1 ohm, then another inch of 1 ohm, totalling 3 ohms.

Did I answer your question, or just get you confused more?
 

Xaiver

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Let me lay out some fictitious numbers for simplicity sake so I can make my question as clear as possible.

Lets say I have a 3" Kanthal wire that is 1.0ohms per inch giving me a total resistance of 3.0ohms.
Now lets say I take some NR wire and twist it together with 1" of my Kanthal wire.
I then twist another 1" of my Kanthal wire on the other end to another strand of NR wire.
This leaves me with 1" of kanthal wire between each of the NR connections.

At 1.0 ohms per inch, would I have a 1.0ohm wire or would I still have a 3.0ohm wire? Basically, does the connection of the NR wire have any effect on the total resistance of the wire?

I hope I made my question simple enough. :confused:

I think that your numbers are making it unrealistic for a lot of people. You shouldn't need anywhere near an inch to wrap together. When I wrap mine together, the wrap is actually like 1/4 inch, with the rest of the NR wire sticking out the other way.

IF you do it properly and make a good tight fisherman's knot, the electricity will follow the path of least resistance (NR wire) to get to ther other terminal of the battery as far as it possibly can. IF you did it that way, your wire would end up being something like 2.5ohms.

The only reason that the R wire gets reduced is because the NR wire is literally clipping it of right there, the excess is used to make the wrap with the NR wire. But, the NR wire has an extremely low resistance, which is why we call it No Resistance wire, it doesn't heat up that much as the electricity passes through it, so it doesn't take away the heat that's supposed to be at the coil.

I almost didn't respond because of how rude your 2nd post on here was. If someone's rude to you, lashing out at them isn't going to solve anything. We're on a forum...it's not like you can actually pick a fight and win or prove anything.

At any rate, simple explanation: The R wire that's used in the twist is essentialy nullified. Electricity will follow the NR wire as far as it can, thus to the end of the twist, if it's twisted properly.

Keep in mind though, the resistance of your coil will change as it gets gunked up and through usage.
 

AndAllThingsWillEnd

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Attempting to understand what you asked:

3 inches long piece of 1-ohm-per-inch kanthal measures 3 ohms resistance.
1 inch of NR wire connected to one end of 1 inch of kanthal wire, and another 1 inch of NR wire connected to other end of kanthal wire. This gives me how much resistance?

If this is indeed what you asked, the total resistance would be 1 ohm. When connected end-to-end, you have 1 inch of 0 ohm, 1 inch of 1 ohm, then 1 inch of 0 ohm. Total is 1 ohm.

The 3 inch length could be thought of as: 1 inch of 1 ohm, then 1 inch of 1 ohm, then another inch of 1 ohm, totalling 3 ohms.

Did I answer your question, or just get you confused more?

This is what I thought it would be, I just don't have a way of measuring. Thanks.
 

Hitmetwice

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Easily understood question.
I would "think" electricity, like water would follow a path of least resistance,
therefore it would lower overall resistance substantially but I'm no rocket scientist.
Maybe not right down to 1ohm but substantially less than 3 I'd guess.
Just my theory.

Yes there are no stupid questions, but answers? This may be one.lol
But I think not:vapor::vapor:
 

AndAllThingsWillEnd

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I'm really not the person to call someone out, but I think tobarger was just beyond negative. Just because someone doesn't answer right away doesn't mean this is a stupid question, quite the opposite. I just think this is a question for people who have been doing this a while that they came to the same point as us and wanted to figure it out. Thanks for everyone that helped.

Edit: After reading some of his posts, he may a Genesis guy that doesn't use non resistance wire which would explain why he didn't understand the question. However I still think he shouldn't have responded the way he did.
 
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nebulas

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Attempting to understand what you asked:

3 inches long piece of 1-ohm-per-inch kanthal measures 3 ohms resistance.
1 inch of NR wire connected to one end of 1 inch of kanthal wire, and another 1 inch of NR wire connected to other end of kanthal wire. This gives me how much resistance?

If this is indeed what you asked, the total resistance would be 1 ohm. When connected end-to-end, you have 1 inch of 0 ohm, 1 inch of 1 ohm, then 1 inch of 0 ohm. Total is 1 ohm.

The 3 inch length could be thought of as: 1 inch of 1 ohm, then 1 inch of 1 ohm, then another inch of 1 ohm, totalling 3 ohms.

Did I answer your question, or just get you confused more?

Thanks! That is exactly what I was asking!
 

nebulas

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I think that your numbers are making it unrealistic for a lot of people. You shouldn't need anywhere near an inch to wrap together. When I wrap mine together, the wrap is actually like 1/4 inch, with the rest of the NR wire sticking out the other way.

You are right. I just felt like my question was hard enough to put into words so I tried to keep the example as simple as possible that way it would be easy for people to convert into their own real world uses.:p
 

tobarger

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I went back to the original post and reread the question at least another 10 times
And there is still absolutely no way that I can make any sense of it without a diagram
The more I read it, the more I need a diagram
I thought maybe the OP was trying to describe dual coils in parallel without using the words dual, coil or parallel
But on further review, no that wasn't it either
I see the term "NR wire" used 4 times in the "Question"
Is it possible that the OP does not know that NR stands for "No Resistance"?

Sorry nebulas
I'm glad others answered your question for you
Even though I still can't figure out what the question was

BTW
I have two degrees in electronics
One in Electronics Engineering
And one in Biomedical Technology
If I can help you, I will
 
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Papa Lazarou

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Is this kind of what you meant in the original question? (yes I have too much time on my hands :laugh: )

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