So, I found information that supports that it takes ~120 calories to heat one gram of propylene glycol around boiling. I then found there were 8.8ml per gram of propylene glycol = 120c/8.8ml = 13.6364 calories per milliliter. I then further reduced it to the ~20-drop-per-ml estimate and found 0.6818 calories were required to heat one drop of PG to boiling. One calorie equals 4.184 Joules, which is proportional to wattage over time. So, 0.6818*4.184 = 2.85J/drop.
So, in theory, to vaporize 100% of a drop in one second, we should only need a bit over 2.85W, whereas some units run at as many as nine watts and still don't vaporize a whole drop in one second.
This is another concern of mine - our atomizers' casings are absorbing the heat which would otherwise vaporize the liquid. This is, of course, mostly due to the ceramic cups and metal mesh, which are integral parts of non-tank atomizers.
If one could thermally isolate and regulate the coil while still reliably delivering fluid (as is kinda' done with Genesis models), battery life would extend, coil life would extend and juice would go further since none would be burnt.
Thoughts?
So, in theory, to vaporize 100% of a drop in one second, we should only need a bit over 2.85W, whereas some units run at as many as nine watts and still don't vaporize a whole drop in one second.
This is another concern of mine - our atomizers' casings are absorbing the heat which would otherwise vaporize the liquid. This is, of course, mostly due to the ceramic cups and metal mesh, which are integral parts of non-tank atomizers.
If one could thermally isolate and regulate the coil while still reliably delivering fluid (as is kinda' done with Genesis models), battery life would extend, coil life would extend and juice would go further since none would be burnt.
Thoughts?