Don't have permissions to post this in the Lavatube forum so...
I think I have this Lavatube V.1.5T, or whatever you call the new one figured out.
I am talking about the new lavatube with the same colored buttons as the body, resitance checking,
zombie shutdown mode, etc...
I am an electronic technician. Hope this finds other techy people to refine...
I have a tektronix oscilloscope, which I used to see the voltage unloaded.
At 3 volts on the LT display I got 3.1 volts on a voltmeter. The scope showed
a 6.2 volt peak pulse. The pulses on the scope were 50% duty cycle. (Half of the time 6.2 volts,
the other half of the time 0 vdc) The pulse train (PRF) seems very stable at 100 hz, or 10 msec per prt.
The pulse width "on time" changes based on the volts I set on the lavatube display.
Example: I set the LT to 4.2 volts. 4.2v avg / 6vpk = .7 (70% duty cycle).
THe real peak voltage on MY LAVATUBE unloaded is 6.2V, so 6.2V * .7 duty cycle is 4.34v avg. (What I get)
Volts displayed Duty Cycle Real pk V Volts measured
3.0 50% 6.2v 3.1
4.0 66.7% 6.2v 4.13
5.0 83.3% 6.2v 5.16
6 100 6.2v 6.2
So the PWM scheme seems straight forward to me. How about under load?
I measured 5.338 Vpk on a 3 ohm carto, with the display at 6 volts.
The other voltage settings on the lavatube just changed the pw, as I have described above.
The 5.338 Vpk was always the same. Likewise, on a 2.2 ohm carto I got 4.57 Vpk.
Hmm, where was this changing peak voltage coming from? The PWM scheme stays the same
for all the settings I tried, only the peak voltage changed based on resistance of carto/attomizer.
I put some Hypnotic Mist on my Lavatube, then vaped and pondered...
What if the LT was trying to stay at 9.5 Watts? I tried this theory on a bunch
of different carto resistances and it seems to work perfectly.
Example: (3 ohms)
Step 1: 9.5 watts / 3 ohms = 3.16666666 ("I squared") (p/R=I^2)
Step 2: Sq root of I squared = 1.779513042 amps (get I from I squared)
Step 3: 1.779513042amps * 3 ohms= 5.338 Volts (WooHoo! Thats what I measured)
Example 2: (2.2 ohms) You do the math, I'll just give answers...
Step 1: 4.3181818
Step 2: 2.078023536
Step 3: 4.57 Volts. Again, the same as my measurement
If you figure the peak voltage, based on your carto resistance- that will be what you get
at the 6 volt setting on the lavatube. Settings below the 6 volt one will be scaled down
from this peak voltage by duty cycle, as average voltage.
Example: I have a 2 ohm carto, and I have 4.5 volts on the display. what voltage do I really have?
A 2 ohm carto has 4.35 volts peak possible voltage at the 6 volt setting.
the duty cycle for 4.5 volts is 4.5/6= .75
A .75 duty cycle (because I have 4.5 volts on display) * 4.35 volts (because this is the max I can get with a 2 ohm carto)
gives us an answer of 3.26 volts. This is what you measure with a 2 ohm load.
I could go on, but here is a fine point: From this math, I can see that the new lava tube is most likely
regulated to be below 9.5 watts. Maybe yours is actually 10 or 9 watts, mine is 9.5 watts.
If you had a 3 ohm carto (5.338vpk) on a lavatube showing 4.5v (.75 duty cycle) you would get
an average voltage of 4.0035 volts, same as a freshly charged EGO right??????
Well, the average voltage is the same BUT- the lavatube is spending half it's time putting out 5.338 volts.
You feel like it's really kicking compared to the EGO.
For the same reasons as pulse width modulation is used on motor control circuits, the PWM here gives more
low end torque in the form of vapor, heat, and kick.
The practical limits of this thing seem to be at the low end: a 1 ohm carto will get 3 amps. Probably a limit.
At the other end you reach 6 -ish volts peak voltage with a 4 ohm carto. Volts wont go up any more, so higher ohms
will be less vape.
Sorry if this was too technical. Feel free to rip me on any typos or technical errors!
I think I have this Lavatube V.1.5T, or whatever you call the new one figured out.
I am talking about the new lavatube with the same colored buttons as the body, resitance checking,
zombie shutdown mode, etc...
I am an electronic technician. Hope this finds other techy people to refine...
I have a tektronix oscilloscope, which I used to see the voltage unloaded.
At 3 volts on the LT display I got 3.1 volts on a voltmeter. The scope showed
a 6.2 volt peak pulse. The pulses on the scope were 50% duty cycle. (Half of the time 6.2 volts,
the other half of the time 0 vdc) The pulse train (PRF) seems very stable at 100 hz, or 10 msec per prt.
The pulse width "on time" changes based on the volts I set on the lavatube display.
Example: I set the LT to 4.2 volts. 4.2v avg / 6vpk = .7 (70% duty cycle).
THe real peak voltage on MY LAVATUBE unloaded is 6.2V, so 6.2V * .7 duty cycle is 4.34v avg. (What I get)
Volts displayed Duty Cycle Real pk V Volts measured
3.0 50% 6.2v 3.1
4.0 66.7% 6.2v 4.13
5.0 83.3% 6.2v 5.16
6 100 6.2v 6.2
So the PWM scheme seems straight forward to me. How about under load?
I measured 5.338 Vpk on a 3 ohm carto, with the display at 6 volts.
The other voltage settings on the lavatube just changed the pw, as I have described above.
The 5.338 Vpk was always the same. Likewise, on a 2.2 ohm carto I got 4.57 Vpk.
Hmm, where was this changing peak voltage coming from? The PWM scheme stays the same
for all the settings I tried, only the peak voltage changed based on resistance of carto/attomizer.
I put some Hypnotic Mist on my Lavatube, then vaped and pondered...
What if the LT was trying to stay at 9.5 Watts? I tried this theory on a bunch
of different carto resistances and it seems to work perfectly.
Example: (3 ohms)
Step 1: 9.5 watts / 3 ohms = 3.16666666 ("I squared") (p/R=I^2)
Step 2: Sq root of I squared = 1.779513042 amps (get I from I squared)
Step 3: 1.779513042amps * 3 ohms= 5.338 Volts (WooHoo! Thats what I measured)
Example 2: (2.2 ohms) You do the math, I'll just give answers...
Step 1: 4.3181818
Step 2: 2.078023536
Step 3: 4.57 Volts. Again, the same as my measurement
If you figure the peak voltage, based on your carto resistance- that will be what you get
at the 6 volt setting on the lavatube. Settings below the 6 volt one will be scaled down
from this peak voltage by duty cycle, as average voltage.
Example: I have a 2 ohm carto, and I have 4.5 volts on the display. what voltage do I really have?
A 2 ohm carto has 4.35 volts peak possible voltage at the 6 volt setting.
the duty cycle for 4.5 volts is 4.5/6= .75
A .75 duty cycle (because I have 4.5 volts on display) * 4.35 volts (because this is the max I can get with a 2 ohm carto)
gives us an answer of 3.26 volts. This is what you measure with a 2 ohm load.
I could go on, but here is a fine point: From this math, I can see that the new lava tube is most likely
regulated to be below 9.5 watts. Maybe yours is actually 10 or 9 watts, mine is 9.5 watts.
If you had a 3 ohm carto (5.338vpk) on a lavatube showing 4.5v (.75 duty cycle) you would get
an average voltage of 4.0035 volts, same as a freshly charged EGO right??????
Well, the average voltage is the same BUT- the lavatube is spending half it's time putting out 5.338 volts.
You feel like it's really kicking compared to the EGO.
For the same reasons as pulse width modulation is used on motor control circuits, the PWM here gives more
low end torque in the form of vapor, heat, and kick.
The practical limits of this thing seem to be at the low end: a 1 ohm carto will get 3 amps. Probably a limit.
At the other end you reach 6 -ish volts peak voltage with a 4 ohm carto. Volts wont go up any more, so higher ohms
will be less vape.
Sorry if this was too technical. Feel free to rip me on any typos or technical errors!