Nic in Mg, but at what liquid volume?
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Yes, it is.
You got it right! Now for the 1,000,000 dollar question are you up to the challenge? heheee
(I AM off work today, and I have been drinking and paroozing... just to set the record straight.)
You got it right! Now for the 1,000,000 dollar question are you up to the challenge? heheee
(I AM off work today, and I have been drinking and paroozing... just to set the record straight.)
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1ml of 24mg = 24mg nicotine
1/2mil of 24 = 12mg
from a standard Dekang 10ml bottle, approximately 20 drops = 1 mil, therefore, each drop of 24mg = approximately 1.1 mg nicotine
a 10ml bottle will have 10x24mg = 240mg total nicotine
Hope this helps!
TTRP
1/2mil of 24 = 12mg
from a standard Dekang 10ml bottle, approximately 20 drops = 1 mil, therefore, each drop of 24mg = approximately 1.1 mg nicotine
a 10ml bottle will have 10x24mg = 240mg total nicotine
Hope this helps!
TTRP
Ok, now I am REALLY confused.
What a couple of you are saying is that if I used 1ml of 60mg nicotine in a batch of homemade e-juice and add 1ml of no-nicotine PG or VG, I end up with a 2ml base of 30mg nicotine.
However, if I use only 1/2 ml of 60mg nicotine in a batch of homemade e-juice and add 1/2 ml of no-nicotine PG or VG, I end up with a 1ml base of 15ml nicotine.
Somehow this just not make any sense to me.
_________________
I always thought that even one single drop of 60mg nicotine (for example) contains the strength of 60mg of nicotine but only in one single drop. If I then add one drop of no-nicotine PG/VG I then have a 2-drop base of 30mg strength of nicotine base. If I then add another drop of no-nicotine PG/VG I end up with a 20mg strength of nicotine base.
But if what you are saying is true, then: If I get 40 drops out of 1ml of 60mg strength of nicotine, then 1 single drop of it by itself (60mg divided by 40 drops) only has the strength of 1.5mg of nicotine.
Here's something to consider: If I have one gallon of 89 octane gasoline and pour only half of that gallon into my lawn mower, does that mean that my lawn mower is only running on an octane level of 44.5?
Hey, if I'm reading something wrong here, someone please correct me and tell me that I must be getting too old to understand!
What a couple of you are saying is that if I used 1ml of 60mg nicotine in a batch of homemade e-juice and add 1ml of no-nicotine PG or VG, I end up with a 2ml base of 30mg nicotine.
However, if I use only 1/2 ml of 60mg nicotine in a batch of homemade e-juice and add 1/2 ml of no-nicotine PG or VG, I end up with a 1ml base of 15ml nicotine.
Somehow this just not make any sense to me.
_________________
I always thought that even one single drop of 60mg nicotine (for example) contains the strength of 60mg of nicotine but only in one single drop. If I then add one drop of no-nicotine PG/VG I then have a 2-drop base of 30mg strength of nicotine base. If I then add another drop of no-nicotine PG/VG I end up with a 20mg strength of nicotine base.
But if what you are saying is true, then: If I get 40 drops out of 1ml of 60mg strength of nicotine, then 1 single drop of it by itself (60mg divided by 40 drops) only has the strength of 1.5mg of nicotine.
Here's something to consider: If I have one gallon of 89 octane gasoline and pour only half of that gallon into my lawn mower, does that mean that my lawn mower is only running on an octane level of 44.5?
Hey, if I'm reading something wrong here, someone please correct me and tell me that I must be getting too old to understand!
True...
1ml @ 60mg/ml + 1ml @ 0mg/ml = 2ml @ 30mg/ml
1/2ml of 60mg/ml would be a total of 30mg of nic in that 1/2 a ml... if then cut it with 0mg to make a full ml it cuts the nic again making it 15mg/ml
think of it like a pie... if you have a whole pie in one pan and another empty pan... in order to get equal pie in each pan you have to cut the pie to half pie in each pan...
in the second example...
you only took out a half a pie and empty pan... in order to get equal amounts you cut that in half... so now you have a quarter pie in each pan (cuz you only started with a half)
hope this helps....
now about the drops... the BASE is 60mg/ml... but if you are getting 40 drops per ml then yes you are having 1.5mg nic per drop....
the gasoline isn't going to be a good example... comparing apples and oranges...
From Wikipedia:
Octane rating does not relate to the energy content of the fuel (see heating value). It is only a measure of the fuel's tendency to burn in a controlled manner, rather than exploding in an uncontrolled manner.
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I think your logic is off on this one. The mg of nicotine is a constant. If you add 60mg to any amount of liquid you will have 60mg in the mix. What changes is the mg to ml number. 60mg of nicotine in 1ml of anything will net you a 60mg rating. Add 1ml of another liquid and you changed your rating to 30mg to 1 ml. But your now 2ml concoction still has 60mg of nicotine in it. So a 30ml bottle that is rated at 60mg per 1ml will have 1800mg of nicotine in the bottle. It is confusing but I hope I explained it easily enoughOk, now I am REALLY confused.
What a couple of you are saying is that if I used 1ml of 60mg nicotine in a batch of homemade e-juice and add 1ml of no-nicotine PG or VG, I end up with a 2ml base of 30mg nicotine.
Don
Yes, there's some confusion here.
If you mixed 1/2 ml of 60 mg with 1/2 ml of 0 mg... you would have 1 ml of 30 mg. Not 15 mg.
Here's why, mathematically;
1/2 mL times 60 mg/mL = 30 mg total. That's the total amount of mg (all coming from the 60 mg source)
1/2 mL high nic + 1/2 mL no-nic = 1 mL total fluid.
total final concentration of 30 mg nic per 1 mL total fluid - which is 30 mg/mL
As long as the ratio is the same, so is the final concentration
If you mixed 1/2 ml of 60 mg with 1/2 ml of 0 mg... you would have 1 ml of 30 mg. Not 15 mg.
Here's why, mathematically;
1/2 mL times 60 mg/mL = 30 mg total. That's the total amount of mg (all coming from the 60 mg source)
1/2 mL high nic + 1/2 mL no-nic = 1 mL total fluid.
total final concentration of 30 mg nic per 1 mL total fluid - which is 30 mg/mL
As long as the ratio is the same, so is the final concentration
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