stgardner - if your using a lower resistance 510 atty - then you will actually have a LOWER voltage drop across it than my higher resistance 901. (This makes perfect sense too!)
The thing to remember is that we have a fixed voltage that is split between to resistors (the switch and the atty)
Simple example is to take a 2 ohm atty and a 1 ohm switch (3 ohms combined).
The atty would get 2/3 of the voltage and the switch would get 1/3
Now if we drop the resistance of the atty to 1 ohm and the swtich is 1 ohm
then the voltage would be split equally between the 1 ohm atty and the 1 ohm switch.
Its the ratio that changes between the two.
So for your example of 6.5 Volts with a 2.5 ohm atty
with a 1.2 ohm switch you would get 4.4 volts
with a 0.5 ohm switch you would get 5.4 Volts
The problem is that voltage tells us nothing about how much work is being done.
The only way to measure the work is by determining wattage.
assuming 0.5 ohm switch and 6.5 volt battery
your voltage drop with a 2.5 ohm atty is 5.4 volts, but your wattage is 11.1 watts
my voltage drop with a 3.6 ohm atty is 5.7 volts, but my wattage is only 9.0 watts
Here are some wattages for e-cigs with no resistor switch
3.7 volt battery with a 3.6 ohm resistor - 3.8 watts
3.7 volt battery with a 2.5 ohm resistor - 5.4 watts
6.0 volt battery with a 3.6 ohm resistor - 10.0 watts
6.0 volt battery with a 2.5 ohm resistor - 14.4 watts (snap, crackle, pop)
hope this helps!
The thing to remember is that we have a fixed voltage that is split between to resistors (the switch and the atty)
Simple example is to take a 2 ohm atty and a 1 ohm switch (3 ohms combined).
The atty would get 2/3 of the voltage and the switch would get 1/3
Now if we drop the resistance of the atty to 1 ohm and the swtich is 1 ohm
then the voltage would be split equally between the 1 ohm atty and the 1 ohm switch.
Its the ratio that changes between the two.
So for your example of 6.5 Volts with a 2.5 ohm atty
with a 1.2 ohm switch you would get 4.4 volts
with a 0.5 ohm switch you would get 5.4 Volts
The problem is that voltage tells us nothing about how much work is being done.
The only way to measure the work is by determining wattage.
assuming 0.5 ohm switch and 6.5 volt battery
your voltage drop with a 2.5 ohm atty is 5.4 volts, but your wattage is 11.1 watts
my voltage drop with a 3.6 ohm atty is 5.7 volts, but my wattage is only 9.0 watts
Here are some wattages for e-cigs with no resistor switch
3.7 volt battery with a 3.6 ohm resistor - 3.8 watts
3.7 volt battery with a 2.5 ohm resistor - 5.4 watts
6.0 volt battery with a 3.6 ohm resistor - 10.0 watts
6.0 volt battery with a 2.5 ohm resistor - 14.4 watts (snap, crackle, pop)
hope this helps!