RMS vs MEAN? Help!

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jward015

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I have been using my Zmax for a while, and I know the eighth setting is suppose to be set to Root Mean Squared. I've heard that RMS is more accurate so I leave it on that setting. However I'd like to know exactly what is happening inside my device when I change this setting. Any help will be great, thanks guys!
 

zoiDman

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I have been using my Zmax for a while, and I know the eighth setting is suppose to be set to Root Mean Squared. I've heard that RMS is more accurate so I leave it on that setting. However I'd like to know exactly what is happening inside my device when I change this setting. Any help will be great, thanks guys!

Here I a Watered Down explanation of Root Mean Squared.

BTW - How technical to you want an Explanation to be?
 

jward015

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Here I a Watered Down explanation of Root Mean Squared.

BTW - How technical to you want an Explanation to be?


So I just posted two wrong threads lol. I've been vaping for a years now, but I'm new to the forums, obviously. Just explain it the best way possible, the more technical the better
 

ca_girl2tx_girl

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sailense

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Here's a basic breakdown.

The average or mean setting is the sum of those numbers divided by the number of items.

So, if you have 4 readings of 3, 6, 3, 6, the mean/avg is:
3+6+3+6 = 18
18/4 = 4.5

For RMS, we square the items then take the square root:
3^2 + 6^2 + 3^2 + 6^2 = 90
90/4 = 22.5
square root of 22.5 = 4.74

So, using the average we get a value of 4.5 and using rms we get a value of 4.74.

But why is rms more "accurate"?

Well, Power can also be defined as:

P = V^2/R

From this, you can see that power is proportional to the square of the voltage and not the voltage directly.

There's a better explanation here: SmartGauge Electronics - RMS volts as opposed to average volts - simple explanation
 

jward015

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Here's a basic breakdown.

The average or mean setting is the sum of those numbers divided by the number of items.

So, if you have 4 readings of 3, 6, 3, 6, the mean/avg is:
3+6+3+6 = 18
18/4 = 4.5

For RMS, we square the items then take the square root:
3^2 + 6^2 + 3^2 + 6^2 = 90
90/4 = 22.5
square root of 22.5 = 4.74

So, using the average we get a value of 4.5 and using rms we get a value of 4.74.

But why is rms more "accurate"?

Well, Power can also be defined as:

P = V^2/R

From this, you can see that power is proportional to the square of the voltage and not the voltage directly.

There's a better explanation here: SmartGauge Electronics - RMS volts as opposed to average volts - simple explanation

So it's pretty much the same equation of turning voltage to power?
 

sailense

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So it's pretty much the same equation of turning voltage to power?

Yeah, kind of. The main idea is when setting the voltage on a VV/VW device. The device doesn't actually put out the specific voltage. It pulses (PWM) 6v a certain number of times over an interval to hit that voltage.

If set for 4.5v like in the example, it fires a certain number of times so that the average is 4.5v. But to you, it seems hotter than 4.5v, and that's because the RMS of 4.74v is actually a better representation of all those pulses. So, setting a device to RMS will mean that it more accurately reflects the expected power output.
 

Bill's Magic Vapor

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Here's a basic breakdown.

The average or mean setting is the sum of those numbers divided by the number of items.

So, if you have 4 readings of 3, 6, 3, 6, the mean/avg is:
3+6+3+6 = 18
18/4 = 4.5

For RMS, we square the items then take the square root:
3^2 + 6^2 + 3^2 + 6^2 = 90
90/4 = 22.5
square root of 22.5 = 4.74

So, using the average we get a value of 4.5 and using rms we get a value of 4.74.

But why is rms more "accurate"?

Well, Power can also be defined as:

P = V^2/R

From this, you can see that power is proportional to the square of the voltage and not the voltage directly.

There's a better explanation here: SmartGauge Electronics - RMS volts as opposed to average volts - simple explanation

Very nicely done.
 
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