the first question is a little more difficult; K Tech and i were bouncing around some ideas above, but the fact remains that it's not easy to accurately measure the resistance of a mod without some pretty good equipment. the device he has access to can measure in the range of micro-ohms (that's one millionth of an ohm), which is definitely good enough, but then the problem becomes hooking it up correctly to take an accurate measurement.
the answer to your second question is yes. the voltage drop across everything (mod and atty) will always be the same as the voltage of your battery, meaning if your battery is at 4v, the voltage drop across the mod plus the voltage drop across the atty will add up to 4v. obviously, if more voltage goes to your mod, less goes to your atty, which is why mods with a low voltage drop are seen as better.
the way these drops are related is by the resistance. for the sake of simplicity, let's say the mod's resistance is 1 ohm and the atty's is 2 ohms. in this case, the atty will have twice the voltage drop of the mod. since we know that the battery is at 4v (and therefore the total voltage drop must add up to 4), we can calculate that 1.33v will go to the mod, and 2.67v to the atty.
if we keep the same mod and replace the 2 ohm atty with a 3 ohm atty, we now know that the atty will have 3x the voltage drop of the mod. in this case, 3v will go to the atty, and only 1v will go to the mod.
does this make sense? i try not to get too technical, but i work with electricity every day, so my perception of what's "too technical" may be a bit skewed...
also, your second question is brilliant. we don't have to directly measure the resistance of the mod if we can (VERY) accurately measure the difference between the total voltage drop vs the drop over the atty... jkuro's tests are good, but not quite accurate enough if he's getting 0.00v drops in some cases.
hmm, this gives me an idea, now if only i had some (very expensive) voltmeters...
yes. makes total sense. Your examples are illustrative of the flow of energy of batt output. i learned something today.
Learning the DC (?) or resistance of the mod would clarify, verify the "this mod hits like a freight train" type of spec and separate the mech from the atomizer... but a question; doesn't the atomizer body contribute to v loss as well? or does the coil resistance alone represent the total atomizer resistance?