I understand ohms law and I know my clearo is 2.2 and I usually vape at 3.6 volts but what is resistance and why does it matter? Can someone give me a full rundown on everything I would need to know about this topic. Don't spare any details pls.
What is everything I need to know about ohms?
- Thread starter BigOlNoob
- Start date
- th_trl_thread_readers 0
- Status
Search for one stop noob shop on the forum, it has tons of good information all about rebuilds. I'll find it and paste it here. Happy rebuilding 
Understanding ohms law and not knowing what resistance is seems sort of odd.
That being said, if you just want to know how resistance, voltage, and wattage affect your vaping experience, there's a chart at the following link that's a good reference:
Safe Vaping Power Chart: FastTech Forums
To get you in the ballpark, a good thumbrule is to add resistance plus 2 for a "good" voltage setting on your device.
Honestly, it's really not that important to have an in-depth knowledge of Ohm's Law for the casual vaper, unless you're thinking of getting into rebuilding your own coils and/or experimenting with rebuildable atomizers, but a general understanding is helpful.
That being said, if you just want to know how resistance, voltage, and wattage affect your vaping experience, there's a chart at the following link that's a good reference:
Safe Vaping Power Chart: FastTech Forums
To get you in the ballpark, a good thumbrule is to add resistance plus 2 for a "good" voltage setting on your device.
Honestly, it's really not that important to have an in-depth knowledge of Ohm's Law for the casual vaper, unless you're thinking of getting into rebuilding your own coils and/or experimenting with rebuildable atomizers, but a general understanding is helpful.
I'm still learning myself so I don't know if this helps...
2.2ohms is your resistance, if you understand ohms law(I don't)..you probably know that a certain level of resistance will draw a certain level of amps from your battery..
The lower your resistance is, the higher the amp draw will be.
If you use a 10 amp battery, your coils resistance should be no lower than .8ohms..
Veterans please correct me if I'm wrong..
2.2ohms is your resistance, if you understand ohms law(I don't)..you probably know that a certain level of resistance will draw a certain level of amps from your battery..
The lower your resistance is, the higher the amp draw will be.
If you use a 10 amp battery, your coils resistance should be no lower than .8ohms..
Veterans please correct me if I'm wrong..
Last edited:
resistance is the action created by a material that limits electron flow thru the material.
analogy: you have a garden hose no nozzle with the water on full, water is flowing freely thru the hose ( minimal resistance). You grab the hose and begin to kink it. As you kink the hose the water is now encountering a resistance, the flow out of the hose is reduced and the pressure in the hose between the supply and kink begins to build back up to the supply source pressure ( this refers to voltage drop).
analogy: you have a garden hose no nozzle with the water on full, water is flowing freely thru the hose ( minimal resistance). You grab the hose and begin to kink it. As you kink the hose the water is now encountering a resistance, the flow out of the hose is reduced and the pressure in the hose between the supply and kink begins to build back up to the supply source pressure ( this refers to voltage drop).
Resistance is a measure of an object's ability to conduct current in an electrical circuit.
Bunny's analogy is a good practical explanation.
Voltage is the "push" in an electrical circuit. "Amps" are what "come out". The higher the resistance of a component in the circuit, the more Voltage is needed to "push" the current.
Why it matters in vaping: in your case, with a 2.2ohm coil @ 3.6volts... you will get 5.89 watts in your coil. If we drop to say a 1.5ohm coil, the same 3.6volts will give you 8.64 watts, if we raise to a 3.0ohm coil at the same 3.6 volts, you will get 4.32 watts.
Watts(power)=Voltage X Current, so watts & current are directly related.
The magnitude of amps running your coil is what determines the amount of vaporization the coil can do.
Bunny's analogy is a good practical explanation.
Voltage is the "push" in an electrical circuit. "Amps" are what "come out". The higher the resistance of a component in the circuit, the more Voltage is needed to "push" the current.
Why it matters in vaping: in your case, with a 2.2ohm coil @ 3.6volts... you will get 5.89 watts in your coil. If we drop to say a 1.5ohm coil, the same 3.6volts will give you 8.64 watts, if we raise to a 3.0ohm coil at the same 3.6 volts, you will get 4.32 watts.
Watts(power)=Voltage X Current, so watts & current are directly related.
The magnitude of amps running your coil is what determines the amount of vaporization the coil can do.
Last edited:
Actually, my calc show a little over .5 ohm would be 80% of full load on a 10 amp battery, or 8 to 8.4 amps. 0.8ohms would only be 50% of full load, or 5.2 amps.
Not exactly..
... If you substitute Watts for the Amps in your statement the numbers are correct.Watts are the closest measurement in electronic jargon to the heat produced to vaporize our juice. Same as a 100 watt light bulb gives you more light that a 75 watt bulb (more heat also). At the same voltage lower resistance will produce more watts, higher resistance less watts, amperage also but if you're vaping a coil above 1.8Ω - 2.0Ω, the amps are safe for any battery on the market.
Perfect calculations, but the 50% of full load would allow you a 'Factor of Safety' that a good engineer would include in any build. It makes allowances for battery age, increases in internal resistance, changes in internal crystalline structure of the chemicals, loss of specifications due to stress, over or fast charges or discharges, effects of heat or cold....and the other engineering concept that is used 'Factor of Ignorance' that would be used when a human being it factored into the specifications.
http://en.wikipedia.org/wiki/Factor_of_safety
Last edited:
Not exactly..
Watts are the closest measurement in electronic jargon to the heat produced to vaporize our juice. Same as a 100 watt light bulb gives you more light that a 75 watt bulb (more heat also). At the same voltage lower resistance will produce more watts, higher resistance less watts, amperage also but if you're vaping a coil above 1.8Ω - 2.0Ω, the amps are safe for any battery on the market.
Crap! You're right! Too much going on at once at the moment!!
Resistance = friction working against the flow of electricity.
Friction generates heat. We use "resistance wire" because it's designed to have some resistance....fairly evenly...and hold up to the heat. Thus we have a heating coil.
The longer the wire...the more total resistance from end to end. The thinner the wire, the more resistance there is compared to thicker wire (think garden hose vs fire hose).
Ohms just measure that resistance. It quantifies it. Doesn't say what it will do or why it's there. It's a measurement. Can be taken by a meter, even though the meter doesn't know what it is testing (an e-cig coil or a hose wire or a resistor for electronic circuits; all have ohms).
Without resistance in a circuit...you have a "short". It will fry the battery asking it to put out too much electricity per second and heating it up (because of it's own internal resistance).
Too much resistance and the electricity won't flow sufficiently. Too little, and too much can flow.
Voltage = pressure (really difference in potential between battery poles). Amps = electron flow rate at that voltage and through that resistance.
Watts = work done. It doesn't exist in isolation. It's really a "combo number"...a result calculation. It can be calculated from any two of the others (volts, amps, ohms). In fact, given any two of ohms, amps, volts, watts, you can calculate the other two. See Ohm's law and Joule's law. Basically V=IR & P=VI. Algebra will get you all the formulas, or look it up, or use an Ohm's law calculator.
Friction generates heat. We use "resistance wire" because it's designed to have some resistance....fairly evenly...and hold up to the heat. Thus we have a heating coil.
The longer the wire...the more total resistance from end to end. The thinner the wire, the more resistance there is compared to thicker wire (think garden hose vs fire hose).
Ohms just measure that resistance. It quantifies it. Doesn't say what it will do or why it's there. It's a measurement. Can be taken by a meter, even though the meter doesn't know what it is testing (an e-cig coil or a hose wire or a resistor for electronic circuits; all have ohms).
Without resistance in a circuit...you have a "short". It will fry the battery asking it to put out too much electricity per second and heating it up (because of it's own internal resistance).
Too much resistance and the electricity won't flow sufficiently. Too little, and too much can flow.
Voltage = pressure (really difference in potential between battery poles). Amps = electron flow rate at that voltage and through that resistance.
Watts = work done. It doesn't exist in isolation. It's really a "combo number"...a result calculation. It can be calculated from any two of the others (volts, amps, ohms). In fact, given any two of ohms, amps, volts, watts, you can calculate the other two. See Ohm's law and Joule's law. Basically V=IR & P=VI. Algebra will get you all the formulas, or look it up, or use an Ohm's law calculator.
Last edited:
Lower resistance will result in higher amps along with higher watts at the same voltage. Higher voltage will do the same with the same resistance. Hotter comes with the increased amps/watts, faster or slower heating can depend on the size and shape of the coil, what gauge wire used, how much air flow, how much juice flow, wicking....
- Status
Similar threads
- Locked
- Locked
