Fogger V4!!

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AMDTrucking

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^OOOH OOH. Is the airhole actually 2.7 mm? :O

Also curious about the airhole, but more curious about the 6 little holes toward the bottom, are they any larger than stock?

Yes, I've measured it. it is 2.7mm. 6 little holes in the hexagon are the same size as stock pin 1.0mm each,


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AMDTrucking

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Actually, AMD, the six 1mm holes are bigger than 6mm. I haven't done the math, but the total surface area and cubic capacity would be greater than a single 6mm.

You are right. I was thinking six 1 X 1 square holes = one 6 X 6 square hole. But the point was, that those six 1mm holes are NOT going to be a bottleneck in the way of the air though 2.7mm main hole.
 
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ThunderDan

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Yes, I've measured it. it is 2.7mm. 6 little holes in the hexagon are the same size as stock pin 1.0mm each,


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Thanks, I was curious, already drilled out my KF4 center post to 7/64, and don't really sub ohm on it, so I guess I don't really need the kit.

Speaking of 7/64, I went nuts on the fogger 4.4 tonight:

IMG_20150211_233227.jpg

I did a pretty crappy job, but its foggin it up, finally feel like it lives up to the name. I carefully remounted the 26g coils I had wrapped yesterday (lazy), they came out to .43 ohm today. I used slightly less cotton this time, wicking fine now, keeping up at 30-35W without needing primer puffs.

That was a fun project, and now maybe I'll actually use the fogger a bit more, well at least until my Goblin shows up, heh.
 

dwcraig1

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Actually, AMD, the six 1mm holes are bigger than 6mm. I haven't done the math, but the total surface area and cubic capacity would be greater than a single 6mm.

I think you may want to do the math because my calculations indicate that six 1 mm holes has 2 x the restriction of a single 6 mm hole.
So after going back and seeing what the actual subject is, here it is as pertains to six 1 mm holes with a 2.7 mm center pin.
Without figuring drag due to length the six holes are slightly larger.
Six 1mm circles has the same squared area as a 3 mm circle
That kind of puts the 4 X part out the window so I'm changing it to 2 x
 
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TheKiwi

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No disagreement at all, my error in remembering plumbing specs, LOL.

Haha I know... But you know what I mean! I always appreciate it when I see folks having a proper discussion than getting all heated up. Wub.


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dwcraig1

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According to area coverage formula, 2.7 mm hole covers 5.72265 square millimeters.

Six 1 mm holes cover 4.71 square mm of area.

Therefore 6 little 1 mm hole will create a bottleneck for the airflow by whopping 1 square millimeter.

s_kruga.png

I guess because no formula was used by me so I only came close. I'm surprised that they don't equal 3 mm though.

Edit: But now I got a problem, as I said I didn't use a formula so I then did use a formula and got 4.71 sq. mm in 3 mm circle.
Also for 2.7 mm I got 4.239 sq. mm
I'm using 3.14 for pi (close enough)

There's too much going on in above formula, it is more simple than that.
S=R x pi
S= 1.50 x 3.14 (3 mm circle)
S = 4.71 sq. mm

Will the real Mr. Square Millimeter please stand up.
 
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awsum140

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I checked it by using the plumbing pipe capacity comparison. I figure that volume through a tube, is volume through a tube be it water or air, although the coefficient of friction may be different for the two which would also effect capacity. Then there are the turns involved which also add to that friction.

Can anyone say we're over engineering this?
 
Wowww, this is what I needed to know. I never would have guessed it, the screw behind the screw. Thank you thank you!! Now I understand! Is this usual for many RBA's, not just the fogger, to remove posts? To have this screw under the 510 holding everything in place?

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I broke this screw on my Fogger V5. Does anyone know where I can get a replacement or what type of screw I could use that would work?
 

dwcraig1

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I guess because no formula was used by me so I only came close. I'm surprised that they don't equal 3 mm though.

Edit: But now I got a problem, as I said I didn't use a formula so I then did use a formula and got 4.71 sq. mm in 3 mm circle.
Also for 2.7 mm I got 4.239 sq. mm
I'm using 3.14 for pi (close enough)

There's too much going on in above formula, it is more simple than that.
S=R x pi
S= 1.50 x 3.14 (3 mm circle)
S = 4.71 sq. mm

Will the real Mr. Square Millimeter please stand up.

It seems to me that AMD got it right
 
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