Of course, all you have to do is change the resistance of the load.Dont want to switch the topic on this thread but i would have to disagree. On the fact that you can get different amps at the same voltage. Yes it does have to do with ohms law you cant get around that.
Charging a LiIon battery isn't quite such a simple operation. And your argument assumes that the 510 and eGo battery present the same load during charging. Do they? I don't know. What I do know, from reading at Battery University, is that larger batteries can be charged at a faster rate. Also, are you sure that the actual voltage supplied by both chargers is constant at 4.2VDC? Or is that just the rated voltage? Or is that the voltage that battery is charged to? There's good info at Battery University -- Charging Lithium Ion Batteries, which should enlighten on the question of why the std. 510 charger has a lower current.But for example a eGo fast charger charges at 4.2 volts and 420mA a 510 battery charger charges at 4.2 volts and delivers 150mA to 200mA. Same voltage different amps and also the reason you will fry a 510 battery on a eGo charger.
I could very well be wrong i am not saying i am right but what the Surprise battery voltages leaves out is a Amp readings on the different batteries. I think it would be interesting to see what the results would be on amp readings on those batteries.
The amperage readings will be exactly what Ohm's Law dictates for the resistive loads. In the case of the eGo, since it's using a PWM circuit, the amperage readings will show pulses as well. I suspect that if you reply to that thread with your questions, you might get some answers. As you say, it's a bit OT here. But higher maH doesn't matter. It's the voltage and resistance that do.
The difference in eGo vaping performance lies in the airflow management provided by the cone.