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I typically run my mech mod around .4ohms. The way I build sometimes, it tends to take a second or three to fully heat up at first, and even then, over the course of a long vape or a series of chain vapes, I can tell it is getting hotter and hotter. A regulated mod solves this problem right? I can pump more volts and therefor get the coils heating up faster, and the chip will work to keep the power at the same level. Is that right?
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You've been redirected to the
rusirius' blog, which takes a detailed explanation, without almost numbers or formulas, about the question. I've taken a quick oversight on that blog and found it interesting and well thought, taking into consideration how hard can be to explain these facts.
But I also find that many mechanical users, when move on VV/VW electronic devices, get a bit lost. As
rusirius well said, they stand focused on the current and/or resistance or their atomizers, forgetting that the amount of heat provided to the atomizer, or the power plus time of firing, is also dependant of the voltage.
It is not so magical after all.
Yesterday I was putting numbers at the question in another thread. If you don't get frightened by numbers, it might be worthwhile to take a look there..... Meanwhile, the important things are:
* In mechanical, you change the power output changing the current (as voltage is fixed by the battery). Power is the product of voltage and current (P = V * I), and to change current, you change the resistance of your atomizer, according to the Ohm's Law: V = I * R. Combining both, P = V
2 / R or P = I
2 * R.
The security limitation factor is the maximum current draw supported by the battery.
It'll be maximum when the battery is fully charged, at 4,2 V, and it'll be, from Ohm's Law, I = 4,20 / R.....but R is the total resistance of the atomizer, battery and the mod, though for most purposes the main resistance that counts is the one of the atomizer. If your calculation shows a current bigger than the maximum supported draw for your battery, you're risking a thermal overrun on it, which could render serious damages.
*
In electronic VV/VW you change power changing the voltage fed to the atomizer, regardless its resistance. The electronic module will change the voltage applied according to the resistance it measures, but the important thing is that it can rise up voltage to gain more power to be fed. And it usually maintain the conditions even if the battery looses voltage output as it drains off, which is a nice plus.
Because the power draw from the battery is essentially the same regardless its voltage output drop, in electronic VV/VW the security would be applied reversed to mechanicals: the security current for the battery is the one at the voltage cut-off, when the electronic module senses the battery is drained or cannot provide enough current due to its state or internal resistance. It is safer because of that, but it is important to provide the VV/VW mod with a decent battery capable of the current draw expected at that voltage cut-off (when the current draw from the battery is maximum). I refer you to my other post in which, incidentally, that current can be calculated using those formulas, or much simpler, just respect the parameter provided by the manufacturer, like the '12 A' for an Evolv's DNA30D.
