Need 11watt drip tank atomizer suggestions.

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The Ocelot

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The Clock Barrens, Fillory
It's The Law

yjju.jpg


V = volts
P = power (watts)
R = resistance (ohms)
I = current (amps)

They are interdependent.
 

nelska

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Mar 26, 2014
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Use any resistance delivery device that the mvp2 will fire, then adjust the power up / down in either watt mode or volt mode to find the vape quality you're looking for.

yeh, sorry man. I guess the stuff I'm talking about just isn't sense-able. But one thing's for sure.. I definitively prefer wattage mode.
 

The Ocelot

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Wait, so the lower the ohms the cooler the vapor?

Voltage is a measurement of input. It is the input coming from the battery into the system. Ohms is a measurement of resistance, it is what impedes the input. Watts are a measurement of output, which is the power (heat) that vaporizes the liquid. The interaction of the voltage and the resistance determines the amount of wattage produced. [I'm purposely leaving amps out of this explanation]

Ohm's%20Law.jpg


The wattage isn't clearly illustrated in the picture, but it is how much of the amp guy is on the other side of the ohm from the volt guy.

The higher the ohms, that is the tighter the rope in the picture, the more volts would be required to produce the same amount of watts.

It is the watts that make the difference; the more watts, the warmer the vape. The interaction between volts and ohms is best illustrated with a fixed voltage battery device. For example:

I have a box mod that produces 3.7 volts. I can't change the volts, but I can change the devices that I put on it, which come in different resistances.

If I put a 2.2ohm atomizer on my 3.7 volt box mod it will produce 6.2 watts. But if I put a 1.5ohm atty on the same 3.7 volt device it will produce 9.1 watts, which is considerable warmer.

Please refer to the Ohm's Law Wheel I posted earlier for the formulae.
 
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