A little chemistry and nicotine.
Tell me if I am wrong in doing the math:
So the nicotine boosters that we buy have 20 milligrams for every milliliter of liquid
in which they are diluted and therefore if math is not an opinion
each booster has 10ml and therefore 10 x5 = 50 milligrams of nicotine inside.
I found on sale and also without much difficulty
pure nicotine (C10 H14 N2) at about 300 euros for 100 milliliters of 99% pure nicotine
The problem now is to see these milliliters of nicotine how many milligrams contain?
And here we just need to find the specific weight (weight of the unit of volume)
of nicotine which Google's AI easily revealed to me is 1.01 grams per milliliter
For ease of calculation let's consider 99% purity in 100% and that 1.01 in 1.00.
So if 1 milliliter weighs 1 gram, 100 milliliters will weigh 100 grams.
But we need milligrams and not grams, so
100 grams of nicotine results in 100,000 milligrams.
Going back to the argument that math is not an opinion
and that in a nicotine booster there are 50 milligrams of nicotine
with that 300 € we buy 100,000 milligrams of nicotine
we can get by dividing by 50 milligrams contained in a 10 milliliter booster
(100,000 : 50) exactly the amount of nicotine contained in 2000 nicotine boosters!!!!
I guess I have also seen on sale 5ml of the same 99% pure nicotine
for 50€ and in this case dividing it by 20 (100ml to 5ml)
there would be nicotine equal to that contained in 100 10 ml boosters
(2000 : 20 = 100).
Still talking about costs, considering that 2 liters of PG and VG (1l pg + 1l vg)
me being the last wheel of the wagon paid them about 25€,
10ml of pg/vg 50%/50% would cost me 0.125€, while for nicotine
300€ divided by 2000 boosters I would pay for the nicotine of one booster
about 0.15€.
If we add to this the price of an empty 10ml bottle at about 0.15€,
it would come to a total of 0.425€, However, this last count,
leaves time to be found because these are prices of a consumer,
while at the industrial level prices drop at least 10 times if not more.
Let me know first if you think the counts are accurate
and secondly a judgment on how much markup
the booster manufacturers take and tax the states/nations that take advantage of them.
I hope the translation is effective.
So the nicotine boosters that we buy have 20 milligrams for every milliliter of liquid
in which they are diluted and therefore if math is not an opinion
each booster has 10ml and therefore 10 x5 = 50 milligrams of nicotine inside.
I found on sale and also without much difficulty
pure nicotine (C10 H14 N2) at about 300 euros for 100 milliliters of 99% pure nicotine
The problem now is to see these milliliters of nicotine how many milligrams contain?
And here we just need to find the specific weight (weight of the unit of volume)
of nicotine which Google's AI easily revealed to me is 1.01 grams per milliliter
For ease of calculation let's consider 99% purity in 100% and that 1.01 in 1.00.
So if 1 milliliter weighs 1 gram, 100 milliliters will weigh 100 grams.
But we need milligrams and not grams, so
100 grams of nicotine results in 100,000 milligrams.
Going back to the argument that math is not an opinion
and that in a nicotine booster there are 50 milligrams of nicotine
with that 300 € we buy 100,000 milligrams of nicotine
we can get by dividing by 50 milligrams contained in a 10 milliliter booster
(100,000 : 50) exactly the amount of nicotine contained in 2000 nicotine boosters!!!!
I guess I have also seen on sale 5ml of the same 99% pure nicotine
for 50€ and in this case dividing it by 20 (100ml to 5ml)
there would be nicotine equal to that contained in 100 10 ml boosters
(2000 : 20 = 100).
Still talking about costs, considering that 2 liters of PG and VG (1l pg + 1l vg)
me being the last wheel of the wagon paid them about 25€,
10ml of pg/vg 50%/50% would cost me 0.125€, while for nicotine
300€ divided by 2000 boosters I would pay for the nicotine of one booster
about 0.15€.
If we add to this the price of an empty 10ml bottle at about 0.15€,
it would come to a total of 0.425€, However, this last count,
leaves time to be found because these are prices of a consumer,
while at the industrial level prices drop at least 10 times if not more.
Let me know first if you think the counts are accurate
and secondly a judgment on how much markup
the booster manufacturers take and tax the states/nations that take advantage of them.
I hope the translation is effective.