Awesome 
Now I may be not quite getting the full picture, but wouldn't an atty with lower resistance vape differently than a standard one? I mean, resistance=heat=vapor, right? Seems like 10 watts at high ohms would not yield the same output as 10 watts at lower ohms. Power = voltage * current and current = voltage / resistance...
Not trying to be doubtful, just looking to be enlightened as a potential buyer
Now I may be not quite getting the full picture, but wouldn't an atty with lower resistance vape differently than a standard one? I mean, resistance=heat=vapor, right? Seems like 10 watts at high ohms would not yield the same output as 10 watts at lower ohms. Power = voltage * current and current = voltage / resistance...
Not trying to be doubtful, just looking to be enlightened as a potential buyer