Congrats! You get the keys to the executive washroom now!
Oh wow, I just noticed.....I turned Vet today! Someone congratulate me already!
And a decoder ring! Congrats!
gorman said:http://www.tenergy.com/RCR123A-3-0V-750mAh-LiFePO4-Rechargeable-Battery
As maximum discharge current you indicate 450mA. I've heard from other people that the value is mistyped and it should be 3A.
Could you help me understand the true value?
Tenergy said:Thank you for contacting Tenergy.
Max charge and discharge current are all 450mA for this cell.
Higher current will result in reduce of cycle life.
gorman said:Am I right, then, in considering non particulary safe the use of two of these in series (going to 6V) when powering up a resistance of 1.5 ohms?
6/1.5 = 4
So the batteries ought to be able to discharge 4A to be operating within limits, right?
Now, what I think is that the reply makes probably sense in the context of flashlights, where activation is not measuread in seconds but in minutes. I doubt any vaper activates their PV for more than 10-15 seconds, even when dry-burning. If you think about how a flashlight is used, what he's saying sounds probably more believable.Tenergy said:Yes, your calculation is right. This type of use will make the battery extremely hot in a short time.
It will reduce the life of battery rapidly.
There should be no safety issue. Even you short circuit the cell, it should be no fire no explosion.
As to the question of why the postive battery or "top" battery drains faster. The simple answer is because electricity is pulled from the battery from the positive end. When you have stacked batteries the positive end will drain faster becuse its supplying more of the power to the device.
As has been said, swithcing battery positions mid way thru will keep the drain more concistant between the 2 because of this.
If this has been answered already. sorry I'm still sevral pages back.
With all due respect, your answer is not correct. Electricity is not pulled from the positive end. Electricity is flow of negative charged electrons. In case of battery - if battery positive terminal (called anode) is connected to the negative terminal (cathode) via electrically conductive material (atty, piece of metal wire, bulb etc) the electrons will be released from cathode and travel towards anode, thru your circuit over and over again until there are no more free electrons in the cathode. Battery is discharged, and the extra electrons will be supplied via charger. Battery is charged now and processs can be repeated until the chemicals inside are depleted and battery is ready for thrash.
There is nothing magic about positive end. It requires the negative end for electricity to flow from the battery" i.e the same electricity is also "pushed" from negative end.
If you stack two batteries of the same voltage in series (as we do in PV's) total voltage between negative an positive end is double, but the current flowing thru the circuit is the same.
If you connect two batteries in parallel, the voltage would be the highest voltage of them two and if the voltage is different enough, the "stronger" battery will act as a charger for the "weaker" until equilibrium is reached. Each battery thereafter supplies half of the current that would be supplied by each battery in series configuration.
Hope it makes sense, this is just another take on Ohms law.
ANd if I wanted to buy a back-up, is this the correct battery?
AW Orange 18650 3.7v 2000mAh LiMN rechargeable battery
If you use two 3v batteries stacked instead of 1 3.7v battery alone, you'll be vaping at 6v which is a very different experience and will most likely require a different atomizer than you'd use for 3.7v. The non-variable voltage REOs are unregulated, so whatever the math is on your batteries, that's what goes to the atomizer you have screwed on at the moment. If you're using a 1.5ohm LR atty and you fire it up with 6v, you'll probably kill it... or get a painfully hot hit of vapor instead.