Absolutely untrue.
This might blow your mind, but micro coils are big coils.
Big doesn't just mean diameter.
He is saying that, but he's wrong. For example:
Replace "Subohm" with "High Wattage"
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Absolutely untrue.
This might blow your mind, but micro coils are big coils.
Big doesn't just mean diameter.
He is saying that, but he's wrong. For example:
According to the coiner of the term; a "micro-coil" is both tight stacked and small in diameter (compared to traditional coils, about 1/2 the ID). And, I'm afraid this is a popular term, not a technical one.
Just tight stacked? . . .. That's a Jasl90 in my book. A "Jasl-wrap". (Least, that's where I first saw it and learned it. I used to do Jasl90s on my Gennies and Micro-Gens.)
Just tight stacked? . . .. That's a Jasl90 in my book. A "Jasl-wrap". (Least, that's where I first saw it and learned it. I used to do Jasl90s on my Gennies and Micro-Gens.)
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While high wattage with low resistance coils, and high wattage with high resistance coils SOUND comparable to those who have not tried both, they are SUBSTANTIALLY different. Blanket terms do no good other than to confuse.
exactly amps are the difference...
a higher ohm setup at 15 watt setup has less current than a 15watt sub ohm setup the vape is greatly different as many have experienced
depends on what you mean by this but it's either untrue or inconsequential.
so the flow of electricity and coils resistance is untrue or inconsequential??? how could you calculate wattage without amperage??
The physics our electrical and electronic devices we use to vape abide by are inconsequential?
You get a similar amp draw on the battery between mech and regulated at the same wattage (any wattage). You get similar performance from mech and regulated devices on properly built coils, at the same wattage. The former makes the statement untrue, the latter makes it inconsequential.
The physics make it inconsequential. The key issue in my experience is coil mass.
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Two equations:
E = IR
W = EI
solving for W yields W = (E^2)/R
E is voltage in volts, I is amperage in amps, R is resistance in ohms and W is wattage in Watts.
Knowing any two of the above variables allows solving for the other two. A watt doesn't care about what the voltage or resistance or current are as long as the relationship between them is (E^2)/R or EI. A joule is a watt second. Juice doesn't care how it gets heated but does care about joules per square centimeter (on second thought per cubic centimeter but then we get into thermal engineering for atomizers that are not typical and that gets complicated lol).
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both equation use current and it consquentially affects the formulas as well the force pushing the electrons through the wire is wat delivers voltage to the resistance thus creating power
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You're talking about this theoretically. We're talking about it practically.
Either way, "sub-ohm" refers to resistance. "High wattage" is a more broad term. They are different, and cannot be used interchangeably. Period.
He was answering the question, and that is practical ... ohm's law doesn't change in practice.
One is a subset of the other, however referring to resistance is of limited value when it comes to vaping. Any resistance can be arrived at many different ways and they all perform differently.
Exactly...
They are similar like Blu and Sub-ohm are both vaping.
Sent from my mobile, using Tapatalk... so ignore the typos.
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Nope... Same watts...
Very different vape.
Sent from my mobile, using Tapatalk... so ignore the typos.
That's a sentence I don't think I've ever seen on ECF before...
I suspect either because the first half is not true... Our the last half.
Sent from my mobile, using Tapatalk... so ignore the typos.
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Simply untrue.
I routinely vape at 40watts sub-ohm
Do that at 12volts using a coil that fits in an atty and you'd be burning juice like crazy.
Sent from my mobile, using Tapatalk... so ignore the typos.
So where is the representation of temperature of the wire, wire gauge, etc.?
You know, all the factors that make sub ohm what it is.
Sent from my mobile, using Tapatalk... so ignore the typos.
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Both are perfectly true. My single coil octopus at 3.2 ohms actually outperforms my dual coil nimbus at 0.6 ohms at the same wattage.
Not if you build it correctly. Similar coil mass makes for a similar vape, so there's no reason it wouldn't fit in an atomizer.
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No it doesn't.
But thermodynamics effect the vape produced by variations in ohms law.
Ohms law stands up, and a 15 watt vape is identical at all voltages....
UNLESS the wire gauge and/or shape changes... Then differences in thermodynamics take effect and the vape can be very different.
Sent from my mobile, using Tapatalk... so ignore the typos.
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