Keep in mind, folks, that dual coils mean each coil gets half the power, so running at ten watts means each coil is actually getting five watts. Just an FYI.
itaste VTR
- Thread starter greghemmings
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I believe that's wrong. The coils are wired in parallel, not in series. If the user sets the variable power at 10 watts, the coil unit is supplied with 10 watts. That 10 watts is supplied to everything in the circuit.
My 2.1 ohm dual coil Aspire coils develop burnt taste at 8.0 watts and above. My 2.1 ohm dual coil iClear 30S coils do not develop burnt taste until at least 10 watts. The difference is not in the wiring, it's in the ability of the device to supply sufficient juice to the coils.
If you plug two 100 watt light bulbs into the same outlet, each bulb still puts out the same 100 watts of light and heat that it does when only one is plugged in.
in series, current is the same. In parallel current is divided. At least for resistors in DC circuits.
light bulbs are a bad example as they are AC devices and wired in parallel actually.
light bulbs are a bad example as they are AC devices and wired in parallel actually.
Resistance (ohms) is a constant. It doesn't matter whether current is flowing.
A 2.0 ohm dual-coil device, presuming that the coils are identical, has two 4.0 ohm coils that are not distinguished from each other. Since the coils are wired in parallel, a PV can't tell the difference between a 2.0 ohm coil and a pair of 4.0 ohm coils. The current is going to one place, not two places. If you removed one of the two coils, the resistance would double. The device would then have to provide more voltage to achieve a given wattage setting.
If you wire two 100 watt light bulbs in series, then each bulb will only put out 50 watts. But bulbs in households are in parallel circuits and there is no reduction in wattage. The same is true of the coils in a dual-coil device powered by a DC battery. Batteries are not smart enough to know how many items are wired in parallel; to the battery, there is only one place the current is going.
Gad, I even confuse myself. Electrical current is extraordinarily complex, and I'm no electrical engineer, but there are things being said that just ain't so.
You are looking at it incorrectly. You are looking at the simplified circuit and not what happens internally.
for reference look at wikipedia or any intro to electronics book. or the links i am posting here. They will explain it better than i can.
Series and parallel circuits - Wikipedia, the free encyclopedia
Resistors in Parallel
Resistors in Series
for reference look at wikipedia or any intro to electronics book. or the links i am posting here. They will explain it better than i can.
Series and parallel circuits - Wikipedia, the free encyclopedia
Resistors in Parallel
Resistors in Series
In a parallel circuit the current, power, is divided between, in this case anyway, the two coils. The mod sees it as one device, but the power is split between the two. Assuming they are the same exactly the same resistance, not really very likely but fo the sake of argument say they are, each would receive 1/2 the power supplied by the mod, therefor if the mod supplies 10 watts, each coil produces 5 watts for the total of 10 watts supplied. Basically you can say voltage is equal while current and power are divided between the two so their total output is a sum of the two.
The same is true of a series connection. The difference being that it becomes a sum of the power dissipated by each coil. To maintain conditions the coil resistances would have to be decreased by half, making each coil one ohm to achieve the two ohm total. The total power doesn't change since the total resistance is still the same. Each coil will see full current, but the voltage and power will be divided between the two. Equilibrium, and the physics of the situation, is preserved.
No matter how you look at it, Ohms Law is not violated.
This is a simple DC circuit and the rules of DC apply to it. The inductance and capacitance of the coils is hardly measureable with normal equipment and is not a factor at all, neither is the pulsing of most regulated mods today. The whole thing works as a simple DC circuit and you can't get around those rules.
The same is true of a series connection. The difference being that it becomes a sum of the power dissipated by each coil. To maintain conditions the coil resistances would have to be decreased by half, making each coil one ohm to achieve the two ohm total. The total power doesn't change since the total resistance is still the same. Each coil will see full current, but the voltage and power will be divided between the two. Equilibrium, and the physics of the situation, is preserved.
No matter how you look at it, Ohms Law is not violated.
This is a simple DC circuit and the rules of DC apply to it. The inductance and capacitance of the coils is hardly measureable with normal equipment and is not a factor at all, neither is the pulsing of most regulated mods today. The whole thing works as a simple DC circuit and you can't get around those rules.
We agree that the coils in a multi-coil juice device are wired in parallel.
We agree that it is impossible to violate Ohm's Law.
However, you've stated that current and power are the same. Current is amps but power is watts. They are two different things.
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The current and power are the same for any configuration, parallel or series, IF the total resistance is the same. I am not implying that current and power are the same thing. I am saying that power is the product of current and voltage working against resistance.
To state it simply, in a parallel coil arrangement the current is divided, in a series circuit the voltage is divided. Power is the same either way as a result, half of the power is generated by each coil.
To state it simply, in a parallel coil arrangement the current is divided, in a series circuit the voltage is divided. Power is the same either way as a result, half of the power is generated by each coil.
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Absolutely right. I stand corrected. In fact I'm going to edit the post where I made the incorrect statement.
The above is correct! On my IGO W RBA if I build two coils,both with a resistance of 2 ohms,the head will read 1 ohm,with both coils attached. Remove 1 coil and it will read 2 ohms.
I saw this on another thread and thought folks here might be interested:
From Vaporworld-
Will be having a huge online Black Friday Sale.
You must go to the website and join our newsletter on our home page first, then on Black Friday you will get a email and we will be having the biggest sale ever seen by a Vapor Store. Some examples are,
VTRs for 49.00
From Vaporworld-
Will be having a huge online Black Friday Sale.
You must go to the website and join our newsletter on our home page first, then on Black Friday you will get a email and we will be having the biggest sale ever seen by a Vapor Store. Some examples are,
VTRs for 49.00
But they'll only have a limited number, and your email address will have to stand in line all night... 
I just got my VTR today, and I love it. Using a 19mm xl IBTanked carto tank. It fixes what I didn't like about the MVP - internal battery, and a carto tank sitting on top is wonky. It's as heavy as my 134, but I like that in a mod. Overall, very pleased.
i got my VTR a couple days ago and last friday i won a j-wrap. so i got the R2D2 VTR j-wrap. can't wait....
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