Chances of an e-cig blowing up in my face?

[KenD]

Just wanted to point out that your Evic mini 2 is a solid device which reads ohms and gives you the current when u press the fire button. A momentary press while u look at the display, current is at the bottom. Think of current like water pressure. Too much pressure can blow up the pipes!! Also a vented battery is one that malfunctions - overheats, vents gases, possible fire or explosion. U can find it on Youtube.

The current readout on the mod (and most other mods that have an amp display) show the amps at the atomizer only, and that's basically useless information. It has no relation at all to the amp draw at the battery. The calculation for that is:

Watts (add 10% to account for chip inefficiency) / battery voltage (highest draw at the lowest voltage so 3.2v is a good number, for a single-battery mod) = amps

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[KenD]

I see others gave links to battery safety for vaping, and that's a great place to start. Most batteries have a maximum current output of 20 to 25 amps. So just take the voltage of your battery, usually 3.7 for single battery mods, divide by the ohms of your build and that will tell you how many amps you're drawing from your battery. If it's more than the battery's 20 to 25 amps, bad things can happen. Stay within the limits, and it's pretty safe vaping! Happy vaping!

Hmmm, no. You need to use the fully charged voltage, 4.2 v. And you need to know the actual constant discharge current of your battery, and know that if the battery is not a Sony, Samsung, or LG then the stated cdr is probably heavily exaggerated.

And that's for mech/unregulated mods. For regulated mods the amp draw calculation is different. See my last post in this thread.

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[beckdg]

Could someone please explain why it is recommended to let the batteries rest for an hour before/after charging? Not saying you shouldn't or anything, i just want to know the reason. Thanks

Superstition carried over from nickel batteries.

The same as learning ohms law and testing resistance on a regulated device. Neither has anything to do with what the battery sees as you set the output on the mod itself.

Tapatyped

 

[beckdg]

This is a controversial safety suggestion based upon anectodal observations. I first learned of it from reading Rolygate's (ECF Forum Manager and battery expert) blog: Warning: Batteries for APV's

"Rest batteries after charging
One commonly-reported factor in almost all the incidents we hear of where batteries failed violently while in use is that they were taken directly off the charger and then used immediately, at which point they failed.

Because of this, we think it may be a good idea to rest batteries after charging them. This advice will not be found in the usual 'reference bibles' on batteries, but we see more and different reports than others. Therefore we now advise:

Do not use batteries directly after charging them. Use a battery or batteries you previously charged, and that have rested for several hours. This is especially important if using a stacked pair for higher voltage, as statistically the risk is far higher.

The benefit to resting is increased battery lifespan & minimize chance of venting."​

I wouldn't call it controversial.

I'd call it dated and not applicable here.

For nickel batteries that have been stressed to the point of gaining heat, it's an absolute must.

For lithium batteries used in a momentary on--->off fashion, it's absolutely useless.

If the battery isn't warmer than human skin and you're using an appropriate charger, that rest period does absolutely nothing.

We should teach people how to properly charge and handle their batteries instead of using superstition to garner an imaginary layer of protection.

Tapatyped

 

[johnm1971]

Hmmm, no. You need to use the fully charged voltage, 4.2 v. And you need to know the actual constant discharge current of your battery, and know that if the battery is not a Sony, Samsung, or LG then the stated cdr is probably heavily exaggerated.

And that's for mech/unregulated mods. For regulated mods the amp draw calculation is different. See my last post in this thread.

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Yeah, it would be 4.2. I mentioned

Hmmm, no. You need to use the fully charged voltage, 4.2 v. And you need to know the actual constant discharge current of your battery, and know that if the battery is not a Sony, Samsung, or LG then the stated cdr is probably heavily exaggerated.

And that's for mech/unregulated mods. For regulated mods the amp draw calculation is different. See my last post in this thread.

Sent from my M7_PLUS using Tapatalk

Yeah, it would be 4.2 fully charged. As far as the maximum current discharge, I was just giving a general example. You can look up for your batteries easily by Googling or searching on this forum and find out all of the stats for your batteries. Thanks.

 

[Zutankhamun]

I use mechs but I don't go low and usually 1.2 so I have no worries.
But a 0.12 build is proper low and your drawing 35 amps!!!
Surely that ain't good for any batteries? Is it the step down that makes this safe because a 10 second cutoff isn't exactly pulsing.

Another thing. I wouldn't bother getting that low of a build for 70 watts.

Can someone explain.

 

[johnm1971]

Yeah, it would be 4.2. I mentioned

Yeah, it would be 4.2 fully charged. As far as the maximum current discharge, I was just giving a general example. You can look up for your batteries easily by Googling or searching on this forum and find out all of the stats for your batteries. Thanks.

Oh, and rounding down on maximum current discharge is always a good idea. I use Samsung 25Rs and NEVER draw over 18 amps. I play it safe. Great point!

 

[KenD]

I use mechs but I don't go low and usually 1.2 so I have no worries.
But a 0.12 build is proper low and your drawing 35 amps!!!
Surely that ain't good for any batteries? Is it the step down that makes this safe because a 10 second cutoff isn't exactly pulsing.

Another thing. I wouldn't bother getting that low of a build for 70 watts.

Can someone explain.

With step down I assume you're talking about regulated mods. .12Ω is indeed too low on a mech, but with a regulated device the resistance doesn't factor into the amp draw. Watts and battery charge are what determine the current draw.

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[Zutankhamun]

With step down I assume you're talking about regulated mods. .12Ω is indeed too low on a mech, but with a regulated device the resistance doesn't factor into the amp draw. Watts and battery charge are what determine the current draw.

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thank you

Well I'm always safe anyway and have overestimated by using I=v/r

My maths is terrible though. I can change for ohms law
but is that this "watts law" I hear so much about.

Even still, I like to go 50% of the cdr and 25 amps which I've now looked at for .12 @ 70 watts is still too much for me.

I mtl but I think this battle for high wattage and low resistance coils have outweighed the progress of 18650s.
I don't know why they keep going higher and lower (respectively) when you can only get 30 A (proper) batts still.
And many of these mods can only take 1 18650 anyway.

Thanks KenD

 

[beckdg]

I believe it's so the internal temperature can come down. And that most vented batts are during charging or right after it. Someone else can better explain.

Nearly all vented batteries happen during abuse.

Though some are inevitably manufacturing defects as with any consumer commodity.

If you;

Dent your battery and still use it
Otherwise compromise the casing
Overcharge it
Charge it at too high amps
Pull more than its safe discharge
Continue use with a torn insulator
Use a charger of reverse polarity
Connect a charger with no cutoff value installed to an ego with no charge termination value

Etc.

You're asking for negative karma and severely increasing your chances of getting just that.

When you combine these bad practices, consider that a multiplier. It doesn't just "add up".

Tapatyped

 

[HauntedMyst]

Just based on some simple calculations of the USA population, there are an estimated 9 million e-cig users and an e-cig explosion reported about once a month, which would mean your odds are 1 in 750,000. That's a number for the ecig population as a whole. For the individual, it doesn't take into consideration for their placement on either the IQ or dingleberry scales. The odds can swing the wildly in either direction from about 1 in 8.99 million to 1 in 4 depending where the individual falls on those scales.

 

[SteveS45]

@HauntedMyst LMFAO! Dingleberry Scale! Good One!

 

[daviedog]

While i furtively check my cell temperatures, i also keep an eye out for the Hoop snakes.
Gotta protect the wimmin' folk..

 

[DingerCPA]

Just based on some simple calculations of the USA population, there are an estimated 9 million e-cig users and an e-cig explosion reported about once a month, which would mean your odds are 1 in 750,000. That's a number for the ecig population as a whole. For the individual, it doesn't take into consideration for their placement on either the IQ or dingleberry scales. The odds can swing the wildly in either direction from about 1 in 8.99 million to 1 in 4 depending where the individual falls on those scales.

{Grateful to be tending toward the higher end of the IQ scale and non-existent on the Dingleberry scale}